If 18 August 2000 was Friday, then what was the day of the week on 21 August 2005?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. Sunday.
2000 to 2005 = 5 years (4 ordinary years and 1 leap year)
So, 1 leap year has 2 odd days, and 4 ordinary years have 4 odd days
Total odd days = 2 + 4 = 6
6 odd days = 6/7 = 0 weeks and 6 odd days
Then,18 August 2005 will be Friday + 6 = Thursday
Now, the number of days between 18 August 2005 to 21 august 2005 = 21 - 18 = 3 days
So, 21 August 2005 will be Thursday + 3 = Sunday.