If 16a4 + 36a2b2 + 81b4 = 91 and 4a2 + 9b2 - 6ab = 13, then what is the value of 3ab?
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Correct answer: B
Explanation
The correct answer is option 2 i.e - (3/2)
We have given that,
⇒ 4a2 + 9b2 - 6ab = 13
Squaring both sides,
⇒ (4a2 + 9b2 - 6ab)2 = 169
⇒ 16a4 + 81b4 + 36a2b2 + 2(36a2b2 - 24a3b - 54ab3) = 169
By putting the given value,
⇒ 2(36a2b2 - 24a3b - 54ab3) = 169 - 91
⇒ 36a2b2 - 24a3b - 54ab3 = 39
⇒ -6ab(4a2 + 9b2 - 6ab) = 39
⇒ -6ab = 39 / 13 = 3
⇒ 3ab = -(3 / 2)