SSC CGL 2019 PYQ — Question 61

SSC CGL - 12th June 2019 - Shift 3 • Quantitative Aptitude • Q61

If 12sin θ = 5 cos θ, then sin θ + cos θ – cot θ is equal to:

Show answer & explanation

Correct answer: B

Explanation

Correct Answer is option 2 i.e. -71/65

Concept

Understanding

Application

Fair calculation

tan θ = P/B

sin θ = P/H

cos θ = B/H

cot θ = B/P

Pythagoras theorem:

H2 = P2 + B2

 

Given

12sin θ = 5 cos θ

⇒ tan θ = 5/12 = P/B

Hence,

H = √(52+122)

H = 13

Now,

sin θ + cos θ – cot θ

= 5/13 + 12/13 – 12/5

= -71/65

√(52+122 )

= √(25+144)

= √169 = 13

5/13 + 12/13 – 12/5

= (25 + 60 – 156)/65

= -71/65