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SSC CGL 2018 PYQ — Question 68

SSC CGL Tier II Quant - 09/03/2018 • Quantitative Aptitude • Q68

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If 12A = 16B = 15C; find A : B : C.

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Correct answer: C

Explanation

 The correct answer is option 3 i.e. 20 : 15 : 16

Application

12A = 16B = 15C

So,

A : B = 4 : 3

B : C = 15 : 16

And

A : C = 5 : 4

Hence,

A : B : C = (4 × 5) : 15 : (4 × 4)

= 20 : 15 : 16