If 10 October 2003 was a Friday, then what was the day of the week on 8 October 2015?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. Thursday.
2003 to 2015 = 12 Years (9 Ordinary Years and 3 Leap Years).
So, 3 Leap Years have 6 odd days, and, 9 Ordinary Years have 9 odd days.
Total odd days = 6 + 9 = 15.
15 odd days → 15 ÷ 7 = 2 weeks and 1 odd day.
Then, 10 October 2015 will be Friday + 1 = Saturday.
So, the number of days between 10 October 2015 to 8 October 2015 = 2 days.
So, 8 October 2015 will be Saturday - 2 = Thursday.