SSC CGL 2019 PYQ — Question 69

SSC CGL - 6th June 2019 - Shift 3 • Quantitative Aptitude • Q69

If (1 + tan2x) + (1+ (tan2x)-1) = k, then √k=?

Show answer & explanation

Correct answer: D

Explanation

Correct answer is option 4 i.e. cosecx sec x

       Concept

Understanding

Application

Tan x = Sin x/Cos x

 

Sin2x + Cos2x = 1

 

1/Sin x = Cosec x

 

1/Cos x = Sec x

Put

Tan x

= Sinx/Cosx

 

(1 + (Sin x/Cos x)2) + (1 + (Cos x/Sin x)2) = k

⇒(Sin2x + Cos2x)/ Cos2x + (Sin2x + Cos2x)/Sin2x = k

⇒1/ Cos2x + 1/ Sin2x

⇒ (Sin2x + Cos2x)/ Sin2x Cos2x

⇒ 1/ Sin2x Cos2x

⇒cosec2x sec2x

 

√k = cosec x sec x