If α + β + γ = 0, Then (3β² + α² + γ²)/(2β² - αγ) = ?

If α + β + γ = 0, Then $\frac{3β^2 + α^2 + γ^2}{2β^2 - αγ}$ = ?

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Correct answer: D

Explanation

The correct answer is Option 4 i.e. 2

α + β + γ = 0

⇒ γ = - α - β ...(1

⇒ γ² = α² + β² + 2αβ ...(2

(3β² + α² + γ²)/(2β² - αγ) = ? ...(3

Substituting value of γ from eq(1 and (2 in eq(3 -

⇒ (3β² + α² + γ²)/(2β² - αγ) = ?

⇒ (3β² + α² + α² + β² + 2αβ)/[2β² - α(- α - β)] = ?

⇒ (4β² + 2α² + 2αβ)/(2β² + α² + αβ) = ?

⇒ 2(2β² + α² + αβ)/(2β² + α² + αβ) = ?

⇒ 2 = ?

SSC CPO 2024 PYQ — Question 109