SSC CHSL 2019 PYQ — Question 65

SSC CHSL - 11th July 2019 - Shift 1 • Quantitative Aptitude • Q65

The full marks for a paper is 300. The break-up of the marks into theory (X), practical (Y) and project (Z), Which are the three components of evaluation is 6 : 5 : 4. In order to pass one has to score at least 40%, 50% and 50% respectively in X, Y, Z and 60% in aggregate. The marks scored by four students A, B, C and D are shown in the given Bar Graph.

How much percentage marks more than B has C scored in practical?

Show answer & explanation

Correct answer: D

Explanation

 The correct answer is option 4 i.e. 60

Application

Marks scored by B in practical = 50

Marks scored by C in practical = 80

Hence,

Required percentage = [(80 - 50)/50] × 100

= 300/5

= 60%