How many numbers are there from 101 to 199 which are multiples of 6?
Show answer & explanation
Correct answer: B
Explanation
Given:
Number range = 101 to 199
Divisor = 6
According to the formula:
Number of terms = (Last multiple − First multiple)/6 + 1
The first multiple of 6 greater than 101 = 102
The last multiple of 6 less than 199 = 198
Number of terms = (198 − 102)/6 + 1
= 96/6 + 1
= 16 + 1
= 17