SSC CGL 2025 PYQ — Question 57

SSC CGL - 18 Sep 2025 - Shift 1 • Quantitative Aptitude • Q57

Given x+3+x−2=5\sqrt{x+3} + \sqrt{x-2} = 5, then find the value of x.

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. 6.

 

x+3+x−2=5\sqrt{x+3} + \sqrt{x-2} = 5

⇒ (x+3+x−2)2=52\left(\sqrt{x+3} + \sqrt{x-2}\right)^2 = 5^2

⇒ (x+3)+(x–2)+2(x+3)(x–2)=25(x + 3) + (x – 2) + 2\sqrt{(x + 3)(x – 2)} = 25

⇒ 2x+1+2(x+3)(x–2)=252x + 1 + 2\sqrt{(x + 3)(x – 2)} = 25

⇒ 2(x+3)(x–2)=24−2x2\sqrt{(x + 3)(x – 2)} = 24 - 2x

⇒ (x+3)(x–2)=12−x\sqrt{(x + 3)(x – 2)} = 12 - x

⇒ (x + 3)(x – 2) = (12 – x)2

⇒ x2 + x – 6 = 144 – 24x + x2

⇒ x – 6 = 144 – 24x

⇒ 25x = 150

⇒ x = 150/25 = 6