SSC CGL 2023 PYQ — Question 64

The correct answer is option 3 i.e. $\frac{\pi}{3}$.

Given that, $\sin \theta_1 = \frac{1}{2}$

⇒ $\theta_1 = {\pi \over 6}$

According to the given question,

$\theta_1 + \theta_2 = \frac{\pi}{2}$

⇒ ${\pi \over 6} + \theta_2 = \frac{\pi}{2}$

⇒ $\theta_2 = \frac{\pi}{2} - \frac{\pi}{6}$

⇒ $\theta_2 = \frac{2\pi}{6}$ = $\frac{\pi}{3}$

Hence the value of θ₂ is $\frac{\pi}{3}$.