Given that x8 - 34x4 + 1 = 0, x > 0. What is the value of (x3 - x-3) ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 14
x8 - 34x4 + 1 = 0 x > 0
(x + y)2 = x2 + y2 + 2xy
(x - y)3 = x3 - y3 - 3xy(x - y)
x8 - 34x4 + 1 = 0
x4 - 34 + x-4 = 0 (Multiplying both side by x-4)
x4 + x-4 = 34
x4 + x-4 + 2 = 34 + 2
(x2 + x-2)2 = 36
(x2 + x-2) = 6
x2 + x-2 - 2 = 6 - 2
(x - x-1)2 = 4
(x - x-1) = 2
(x - x-1)3 = 23
(x3 - 3(x - x-1) - x-3) = 8
(x3 - (3 × 2) - x-3) = 8
(x3 - x-3) = 8 + 6
(x3 - x-3) = 14