Given that △DEF~△ABC. IF the area of △ABC is 9 cm2 and that of △DEF = 12 cm2 and BC = 2.1 cm, then the length of EF is :
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. cm
Concept of Similiarity
When two triangles are similar, the lenght of the corresponding side ratios are in square.
Understanding
(area of ΔABC/area of ΔDEF) = (AB/DE)2 = (BC/EF)2 = (AC/DF)2
Application
Let EF = x
BC = 2.1 Given
According to question
(9/12) = (2.1/x)2
Upon solving
x2 = (7 × 7 × 3)/25
x = (7√3)/5
EF = (7√3)/5 cm