George can do 35% of the total work in 6 days. Jim and George together completed a piece of work in 12 days. In how many days could Jim, working alone, complete the entire task?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 40.
Time required for George = (6 × 100)/35 = 120/7 days
Time required for Jim and George = 12 days
Total work = 120 (LCM of 120/7 and 12)
Efficiency of George = 120/(120/7) = 7
Efficiency of Jim and George = 120/12 = 10
Efficiency of Jim = 10 - 7 = 3
Time required for Jim = 120/3 = 40 days
Therefore, Jim, working alone, could complete the entire task in 40 days.