SSC CGL 2022 PYQ — Question 60

SSC CGL - 13 April 2022 - Shift 2 • Quantitative Aptitude • Q60

From the point P on a level ground, the angle of elevation of the top of the tower is 30°. If the distance of point P from the foot of the tower is 510m, then 50% of the height of the tower (in m) is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 85 $\sqrt{3}$

In the above diagram,

PQ = 510 m

Let's assume the height of the tower QR = x cm

In △PQR

tan θ = QR/PQ

tan 30° = x/510

x = 510 × $\frac{1}{\sqrt3}$ = 170 $\sqrt3$

So, the 50% of the height of the tower = 170 $\sqrt3$ /2 = 85 $\sqrt3$ m