From point P, X walks at a speed of 12 km/hr and 6 hours after his start. Y also starts walking from same point P on his cycle after him at the speed of 16 km/hr. How far from the starting point P will Y catch X?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 288 km.
We know that,
Distance = Speed × Time
Speed of X = 12 km/hr
Time X walks before Y starts = 6 hrs
So,
Distance = 12 × 6 = 72 km
Now,
Relative speed = Speed of X - Speed of Y
⇒ 16 - 12 = 4 km/hr
Thus,
Time taken by Y to cover 72 km head start = Distance/Relative speed
Time = 72/4 = 18 hours
During the 18 hours, Y travels at a speed of 16 km/hr
So,
The distance covered by Y = 16 × 18 = 288 km
Hence,
Y will catch X, 288 km from point P