From a point P on a level ground, the angle of elevation of the top of a tower is 30°. If the tower is 110m high, what is the distance (im m) of point P from the foot of the tower?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 330
Let the height of the tower be AB. Tri(PAB) be a right-angles triangle with angle(A) = 90°
We have AB = 110 × (3)1/2 and PA = Distance of point P from the base of the tower
So, tan30° = {110 × (3)1/2}/PA
⇒ PA = 110 × (3)1/2 × (3)1/2 = 110 × 3 = 330