From a point 12 m above the water level, the angle of elevation of the top of a hill is 60º and the angle of depression of the base of the hill is 30º. What is the height (in m) of the hill?
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 48
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Application |
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In the figure: tan30 = 12/BC ⇒ BC = 12√3 m AD = BC = 12√3 m Now in triangle ADE: tan60 = ED/AD ⇒ √3 = ED/12√3 ⇒ ED = 36 m Hence, Height of the hill = CD + DE = 12 + 36 = 48 m |
