Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the letter cluster that is different.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. PBGF.
| Understanding |
|
The logic used here is: Add all the positional values of the letters. 1. LKHZ → 12 + 11 + 8 + 26 = 57 2.PBGF → 16 + 2 + 7 + 6 = 31 3. HJDT → 8 + 10 + 4 + 20 = 42 4. MNBS → 13 + 14 + 2 + 19 = 48 As we can see that 57, 42, and 48 all are multiple of 3, but 31 is not a multiple of 3. Hence, PBGF is the odd one out. |