Five colleagues (A-E) live at house numbers 2, 4, 6, 8, and 10 in a building. A's number is two more than C's; B is at the lowest; D is at the highest; E is between A and D.
Who lives at 6 Elm St.?
Show answer & explanation
Correct answer: D
Explanation
Given house numbers: 2, 4, 6, 8, 10
• B is at the lowest: B = 2
• D is at the highest: D = 10
• Remaining numbers for A, C, and E are 4, 6, 8.
• A's number is two more than C's: C = 4 and A = 6 (since 4 + 2 = 6).
• E is between A and D: E = 8 (between 6 and 10).
The arrangement is:
• 2 → B
• 4 → C
• 6 → A
• 8 → E
• 10 → D
Therefore, A lives at house number 6.