Find three numbers in the ratio of 6 : 4 : 10 such that the sum of their squares is equal to 3800.
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Correct answer: D
Explanation
The Correct answer is option 4 i.e. 30, 20 and 50.
Given that
The three numbers in the ratio of 6 : 4 : 10.
The sum of their squares is equal to 3800
Let the three numbers be 6x, 4x, and 10x
According to the question;
⇒ (6x)2 + (4x)2 +(10x)2 = 3800
⇒ 36x2 + 16x2 + 100x2 = 3800
⇒ 52x2 + 100x2 = 3800
⇒ 152x2 = 3800
⇒ x2 = 3800/152 = 25
⇒ x = 5
So, 6x = 6 × 5 = 30; 4x = 4 × 5 = 20; 10x = 10 × 5 = 50
Hence, the three numbers are 30, 20, and 50.