SSC GD 2023 PYQ — Question 51

The correct answer is Option 3 i.e. $\frac{17}{7}$.

The value of 

⇒ $2\frac{3}{7} \times [(11\frac{2}{6}\div({25\over18} + 2\frac{5}{6} - {7\over36}))] = y \div 72.5\times204$

⇒ ${17\over7} \times [{68\over6}\div({25\over18} + {17\over6} - {7\over36})] = {y\over 72.5}\times204$

⇒ ${17\over7} \times [{68\over6}\div({50\over36} + {102\over36} - {7\over36})] = {y\over 72.5}\times204$

⇒ ${17\over7} \times [{68\over6}\div{145\over36}] = {y\over 72.5}\times204$

⇒ ${17\over7} \times [{68\over6}\times{36\over145}] = {y\over 72.5}\times204$

⇒ ${17\over7} \times [{68}\times{6\over145}] = {y\over 72.5}\times204$

⇒ ${17\over7} \times {408\over145} = {y\over 72.5}\times204$

⇒ ${17\over7} \times{408\over900} \times{72.5\over204} = y$

⇒ y = $\frac{17}{7}$ or 2.42