SSC CGL 2022 PYQ — Question 61

The correct answer is option 2 i.e. 28$\frac{1}{8}$

Concept used:

BODMAS rule :

B = Bracket

O = Of

D = Division

M = Multiplication

A = Addition

S = Subtraction

Calculations:

$\Rightarrow \dfrac{\dfrac{13}{3}+\dfrac{10}{3} \times (\dfrac{9}{5} \times \dfrac{4}{15})\times(\dfrac{25}{4}\times \dfrac{16}{15})}{\dfrac{2}{3}\times \dfrac{6}{5}\times \dfrac{2}{3}}$

$\Rightarrow \dfrac{\dfrac{13}{3} + \dfrac{10}{3} \times \dfrac{12}{25} \times \dfrac{20}{3}}{\dfrac{8}{15}}$

$\Rightarrow \dfrac{\dfrac{13}{3}+ \dfrac{32}{3}}{\dfrac{8}{15}}$

$\Rightarrow\dfrac{225}{8} = 28\dfrac{1}{8}$

Hence the value of  is $28 \frac{1}{8}$ .