SSC CGL 2022 PYQ — Question 74

The correct answer is option 3 i.e. $\frac{1}{6}$

Explanation:

Solving the numerator, we get 

${3\over 2} + {10\over 7} ÷ [{ 8\over 5} of {5\over 4} ] ×{ 7\over 3}$

⇒ ${3\over 2} + {10\over 7} ÷ 2 ×{ 7\over 3} = {3\over 2} + {5\over 3} = {19\over 6}$

Solving the denominator, we get

${8\over 3} ÷{ 4\over 9} × {5\over 6} + 14$

⇒ ${8\over3} × {9\over 4} × {5\over 6} + 14 = 6 ×{ 5\over 6 }+ 14$

⇒ 19

Thus,  = ${({19\over 6})\over 19 }= {1 \over 6}$

Hence the value of  is ${1 \over 6}$ .