SSC CGL 2024 PYQ — Question 52

The correct answer is Option 2 i.e. 1.

We know that,

tan(A - B) =$\frac{ tanA - tanB }{1+ tanA tanB}$

here, A = 72°, and B = 27°

⇒ tan(72° - 27°) = $\frac{ tan72 - tan27 }{1+ tan72. tan27}$

tan 45° = 1

⇒ 1 = $\frac{ tan72 - tan27 }{1+ tan72. tan27}$

⇒ 1 + tan72°.tan27° =  tan 72° − tan 27°

⇒ tan 72° − tan 27° − tan 72° tan 27° = 1