Find the value of (sin6A + cos6A + 3sin2Acos2A) - (sin4A - cos4A + 1)cosec2A.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. - 1.
We know,
(a + b)3 = a3 + b3 + 3ab(a + b)
a2 - b2 = (a - b)(a + b)
sin2A + cos2A = 1
(sin6A + cos6A + 3sin2Acos2A) - (sin4A - cos4A + 1)cosec2A
⇒ [(sin2A)3 + (cos2A)3 + 3sin2A.cos2A(sin2A + cos2A) - ((sin2A + cos2A)(sin2A - cos2A) + 1)cosec2A]
⇒ (sin2A + cos2A)3 - ((sin2A - cos2A) + 1)cosec2A)
⇒ (1)3 - (sin2A + 1 - cos2A)cosec2A
⇒ (1)3 - (sin2A + sin2A)cosec2A
⇒ 1 - (2sin2A)cosec2A [cosec2A = 1/sin2A]
⇒ 1 - 2 = -1