SSC GD 2025 PYQ — Question 49

SSC GD Const 2025 (English) - 07 Feb 2025 - Shift 3 • Quantitative Aptitude • Q49

Find the value of [(21÷7)×{639+142×(4−2)}] \Biggl[ (21 \div 7) \times \Biggl\{ \frac{63}{9} + \frac{14}{2} \times (4 - 2) \Biggr\} \Biggr]

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 63 .

[ (21 ÷ 7) × { 63 ÷ 9 + (14 ÷ 2) × (4 - 2) } ]

[ (3) × { 7 + (7) × (4 - 2) } ]

[ (3) × { 7 + (7) × (2) } ]

[ (3) × { 7 + (14) } ]

[ (3) × { 21 } ]​​​​​​​

= 63