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SSC CPO 2022 PYQ — Question 126

SSC CPO - 11 Nov 2022 - Shift 2 • Quantitative Aptitude • Q126

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Find the value of a in the following equation. (Given a < 10.)

(187÷17×a−3×3)(82−9×7+a2)\frac{(187÷17\times a-3\times3)}{(8^2-9\times7+a^2)}= 1

 

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Correct answer: B

Explanation

The correct answer is option 2 i.e. 1.

(187÷17×a−3×3)(82−9×7+a2)\frac{(187÷17\times a-3\times3)}{(8^2-9\times7+a^2)} = 1

By using BODMAS rule:

(11a - 9)/(64 - 63 + a2) = 1

11a - 9 = 1 + a2

a2 - 11a + 10 = 0

(a - 10)(a - 1) = 0

a = 10, 1

10 is not available in options so a = 1