SSC CPO 2022 PYQ — Question 126

SSC CPO - 11 Nov 2022 - Shift 3 • Quantitative Aptitude • Q126

Find the value of a in the following equation. (Given a < 10).

(187÷17×  a−3×3(82−9×7+a2)=1{(187\div17\times\;a-3\times3 \over (8^2-9\times7+a^2)}=1

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 1

Given that

 (187÷17×  a−3×3(82−9×7+a2)=1{(187\div17\times\;a-3\times3 \over (8^2-9\times7+a^2)}=1

⇒ (11×  a−9)(64−63+a2)=1{(11\times\;a-9)\over (64-63+a^2)}=1

⇒ (11a−9)(1+a2)=1{(11a-9)\over (1+a^2)}=1

⇒ 11a - 9 = 1 + a2

⇒ Put a = 1

11 - 9 = 1 + 1 

2 = 2 (LHS = RHS)

Hence, the required value of a is 1