SSC GD 2025 PYQ — Question 42

SSC GD Const 2025 (English) - 05 Feb 2025 - Shift 2 • Quantitative Aptitude • Q42

Find the value of [(44÷4)×{4848+215×(7−2)}][(44\div 4) \times \{{48 \over 48} + {21 \over 5}\times (7-2)\}]

 

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 242.

  [(44÷4)×{4848+215×(7−2)}][(44\div 4) \times \{{48 \over 48} + {21 \over 5}\times (7-2)\}]

= 11 x { 1 + 21) = 11 x 22 = 242