SSC CGL 2020 PYQ — Question 78

SSC CGL Tier II - Quant - 15 Nov 2020 • Quantitative Aptitude • Q78

Find the value of '?'

{(4/5) × (8/6)2 × 252 × 45} ÷ {128 × 52 × 25} = ?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 12\frac{1}{2}

{(4/5) × (8/6)2 × 252 × 45} ÷ {128 × 52 × 25} = ?

{(4/5) × (64/36) × 625 × 45} ÷ {128 × 25 × 25} = ?

{40000} ÷ {80000} = ?

? = 1/2