SSC GD 2025 PYQ — Question 45

SSC GD Const 2025 (English) - 06 Feb 2025 - Shift 2 • Quantitative Aptitude • Q45

Find the value of [(27×3)×{3÷3×(19−15)4}]\left [ \left ( 27 \times 3 \right )\times \left\{ 3 \div 3 \times \frac {(19-15)}{4}\right\} \right ]

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 81.

[(27×3)×{3÷3×(19−15)4}]\left [ \left ( 27 \times 3 \right )\times \left\{ 3 \div 3 \times \frac {(19-15)}{4}\right\} \right ]

⇒[(27×3)×{1×(19−15)4}]\left [ \left ( 27 \times 3 \right )\times \left\{ 1 \times \frac {(19-15)}{4}\right\} \right ]

⇒[(81)×{1×(19−15)4}]\left [ (81 )\times \left\{ 1 \times \frac {(19-15)}{4}\right\} \right ]

⇒ [ 81 × 1 ]

⇒ 81