SSC CPO 2023 PYQ — Question 120

The correct answer is option 2 i.e.  $\sqrt{\frac{1-sin2A}{cos2A}}$

Given that

The value of $\sqrt{\frac{1-tanA}{1+tanA}}$

⇒ $\sqrt{\frac{1-tanA}{1+tanA}}$

⇒ $\sqrt{\frac{1-(sin A/cos A)}{1+(sin A/cos A)}}$

⇒ $\sqrt{\frac{cos A-sin A}{cos A+sin A}}$

⇒ $\sqrt{\frac{cos A-sin A}{cos A+sin A}\times\frac{(cos A-sin A)}{(cos A-sin A)}}$

⇒ $\sqrt{\frac{(cos A-sin A)^2}{cos^2 A-sin^2 A}}$

⇒ $\sqrt{\frac{1-sin2A}{cos2A}}$