Find the total surface area of a cube, the length of whose diagonal is √108 cm.
Show answer & explanation
Correct answer: D
Explanation
Diagonal of the cube d = a√3
Given:
d = √108 cm
a√3 = √108
a = √108/√3
a = √36 = 6 cm
Now, total surface area of the cube = 6a² = 6 × 6²
= 6 × 36
= 216 sq cm