SSC GD 2025 PYQ — Question 42

SSC GD Const 2025 (English) - 05 Feb 2025 - Shift 1 • Quantitative Aptitude • Q42

Find the third proportional of (3+2)({3 + \sqrt{2} }) and 27{2 \sqrt{7} }.

Show answer & explanation

Correct answer: D

Explanation

 The correct answer is option 4 i.e.  4(3−2)4({3 - \sqrt{2} }).

a : b = b : c

a = (3 + 2\sqrt{2} ) and b = 27\sqrt{7}

c = b2/a​ = ( (27\sqrt{7} )2)/( 3 + 2\sqrt{2} )

⇒ c = 28/ ( 3 + 2\sqrt{2} )

Rationalizing denominator

c =  (28 ( 3 - 2\sqrt{2} ))/(( 3 + 2\sqrt{2} )( 3 - 2\sqrt{2} ))

⇒ c =  (28 ( 3 - 2\sqrt{2} ))/(9 - 2) = 4(3 - 2\sqrt{2} )