SSC CGL 2022 PYQ — Question 67

SSC CGL - 21 April 2022 - Shift 1 • Quantitative Aptitude • Q67

Find the sum of the greatest and the smallest number which may replace k in the number 3281k6 to make the number divisible by 6.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 8

Concept used:

When a number is divisible by 6, it is divisible by both 2 and 3.

Calculations:

When a number is divisible by 2, last digit should be even

When a number is divisible by 3, sum of digits of the number should be divisible by 3.

Divisible by 3 = 3 + 2 + 8 + 1 + k + 6 = 20 + k

For minimum value of k = 1

= 20 + 1 = 21

For maximum value of k = 7

= 20 + 7 = 27

Sum = minimum + maximum = 1 + 7 = 8