Find the sum of the digits of the smallest 6-digit number divisible by 18, 24, and 25.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 9.
L.C.M(18, 24, and 25) = 1800
Now, the smallest 6-digit number is 100000
⇒ 100000/1800 = 55.55
⇒ 56 × 1800 = 100800
Hence, the smallest 6-digit number divisible by 18, 24, and 25 is 100800
Now, the sum of digits od 100800 = 1 + 0 + 0 + 8 + 0 + 0 = 9