Find the sum of all the possible values of (a + b ) , so that the number 4a067b is divisible by 11.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 21
If the alternating sum of the digits is zero or divisible by 11 or then the number is also divisible by 11.
4a067b
= (a +6 + b) - (4 + 0 + 7) = 0 or 11
= (a + b) - 5 = 0 or 11
1st case :
a + b = 5
2nd case :
a + b - 5 = 11
a + b = 16
So, the sum of all possible values of a + b = 5 + 16 = 21