Find the square of the sum of the digits of the smallest number divisible by 18 and 24.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 81.
The smallest number will be by L.C.M
L.C.M(18 and 24)
⇒ 18 = 2 × 3 × 3
⇒ 24 = 2 × 2 × 2 × 3
L.C.M = 72
Sum of digits = 7 + 2 = 9
Square of 9 = 92 = 81