SSC CGL 2025 PYQ — Question 98

SSC CGL - 22 Sep 2025 - Shift 2 • Reasoning • Q98

Find the smallest number which when divided by 8, 9, and 12 leaves a remainder of 5 in each case.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 77.

Number leaves remainder 5 ⇒ Number − 5 is divisible by 8, 9, 12

LCM(8, 9, 12) = 72

So, Number = 72 + 5 = 77