Find the smallest number which, when divided by 6, 8, and 10, leaves a remainder of 5 in each case.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 125.
The required number leaves remainder 5 when divided by 6, 8, and 10.
So, subtract 5 from the number: N − 5
must be exactly divisible by 6, 8, and 10.
LCM of 6, 8, and 10:
LCM = 120
Therefore, N = 120 + 5 = 125
So, the smallest number is 125.