Find the smallest number divisible by the numbers 8, 16, 20 and 32.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 160.
The smallest number divisible by the numbers 8, 16, 20, and 32 = LCM of (8, 16, 20, 32)
⇒ 8 = 2 × 2 × 2
⇒ 16 = 2 × 2 × 2 × 2
⇒ 20 = 2 × 2 × 5
⇒ 32 = 2 × 2 × 2 × 2 × 2
Hence,
L.C.M = 160