Find the smallest natural number 'x' that must be subtracted from 1800 so that (1800- x), when divided by 7, 11 and 23, will leave 5 as the remainder in each case.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 24
LCM of 7, 11 and 23 = 7 × 11 × 23 = 1771
Now,
Adding 5 to the LCM = 1771 + 5 = 1776
So,
The smallest number that should be subtracted from 1800 to get the number divisble by 7, 11 and 23 that leaves 5 as the remainder = 1800 - 1776 = 24