SSC CHSL 2025 PYQ — Question 62

SSC CHSL - 22 Nov 2025 - Shift 1 • Quantitative Aptitude • Q62

Find the remainder on dividing (5x³ + 4x² − 10x + 1) by (2x - 4).

Show answer & explanation

Correct answer: B

Explanation

Given:

P(x) = 5x³ + 4x² − 10x + 1

Divisor = 2x − 4

By the formula:

Remainder Theorem

If the divisor is 2x − 4, then substituting x = 2 gives the remainder:

P(2) = 5(2³) + 4(2²) − 10(2) + 1

= 5(8) + 4(4) − 20 + 1

= 40 + 16 − 20 + 1

= 37