SSC CGL 2025 PYQ — Question 92

SSC CGL - 15 Sep 2025 - Shift 2 • Reasoning • Q92

Find the odd one out.

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 7 @ 1 = 14.

1) 6 @ 2 = 16 → (6 + 2) × 2 = 16 

2) 7 @ 1 = 14 → (7 + 1) × 2 = 16 ≠ 14

3) 7 @ 3 = 20 → (7 + 3) × 2 = 20 

4) 4 @ 4 = 16 → (4 + 4) × 2 = 16 

Thus, 7 @ 1 = 14 is odd one.