Find the number when successively divided 3, 5, and 7 leaving the remainder 2, 1, and 3, respectively, and the last quotient is 3.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 365.
Given that,
The number when successively divided 3, 5, and 7 leaves the remainder 2, 1, and 3, respectively, and the last quotient is 3
We know that,
(Divisor × Quotient) + Remainder = Dividend
According to the question,
⇒ (7 × 3) + 3 = Dividend
⇒ Dividend = 21 + 3 = 24
Now, Second dividend = 24 × 5 + 1 = 120 + 1 = 121
Hence,
The required number = 121 × 3 + 2 = 363 + 2 = 365