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SSC CGL 2025 PYQ — Question 60

SSC CGL - 18 Sep 2025 - Shift 1 • Quantitative Aptitude • Q60

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Find the midpoint of the segment joining (3, 4) and (7, 8)

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. (5, 6).

 

Midpoint (M)=(x1+x22,y1+y22)(M)= \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

For (3, 4) and (7, 8): M=(3+72,4+82)M = \left( \frac{3+7}{2}, \frac{4+8}{2} \right) = (10/2, 12/2) = (5, 6)