Find the least value for * in the number 3*7440 such that it is divisible by 12.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 0.
For a number to be divisible by 12, it must be divisible by 3 and 4.
Check divisibility by 4
Last two digits of 3*7440 = 40 → divisible by 4
Check divisibility by 3
Sum of digits = 3 + * + 7 + 4 + 4 + 0 = (18 + *)
We need this sum to be divisible by 3.
The least * such that (18 + *) is divisible by 3 is 0.