Find the least number which leaves remainder 3 when divided by 5, 7, and 8.
Show answer & explanation
Correct answer: B
Explanation
Let the number be x.
When x is divided by 5, 7, and 8, the remainder is 3 in each case.
x − 3 will be completely divisible by 5, 7, and 8.
LCM(5, 7, 8)
= 280
x − 3 = 280
x = 283