Find the largest value of k such that a 6-digit number 450k1k is divisible by 3.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 7.
Divisibility rule of 3: the sum of the digits must be divisible by 3
Sum of digits: 4 + 5 + 0 + k + 1 + k = 10 + 2k
for k = 7
⇒ 10 + 2 × 7 = 10 + 14 = 24 [divisible by 3]
Thus, the largest possible value of k = 7